The difference between NaOH (s) and NaOH (aq) lies in their physical state and chemical behavior. NaOH (s) refers to solid sodium hydroxide, which exists as a crystalline substance at room temperature. On the other hand, NaOH (aq) refers to sodium hydroxide dissolved in water, forming an aqueous solution. When NaOH dissolves in water, it dissociates into Na+ and OH- ions, resulting in a highly alkaline solution with conductive properties. This difference in physical state and chemical behavior is due to the interaction of sodium hydroxide with water molecules, leading to distinct properties for the solid and aqueous forms. **

To find out how many grams of 15% NaOH can be obtained by diluting 100 liters of 50% NaOH, we can use the formula: C1V1 = C2V2, where C1 is the concentration of the initial solution, V1 is the volume of the initial solution, C2 is the concentration of the final solution, and V2 is the volume of the final solution. Plugging in the values, we get: (50%)(100L) = (15%)(V2). Solving for V2, we get V2 = (50%)(100L) / (15%) = 333.33L. So, 333.33 liters of 15% NaOH can be obtained by diluting 100 liters of 50% NaOH. **

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NaOH is a base because it dissociates in water to produce hydroxide ions (OH-) which can accept protons (H+) from acids, leading to the formation of water. This ability to accept protons makes NaOH a proton acceptor, or a Brønsted-Lowry base. Additionally, NaOH has a pH greater than 7, indicating its alkaline nature. **

NaOH, also known as sodium hydroxide or caustic soda, can be purchased from various sources. It is commonly available at hardware stores, chemical supply companies, and online retailers. It is important to handle NaOH with care as it is a strong base and can cause burns and irritation to the skin and eyes. When purchasing NaOH, it is important to follow safety guidelines and store it in a secure location away from children and pets. **

To determine the amount of NaOH in milliliters, you need to know the concentration of the NaOH solution and the amount of moles required for the reaction. Using the equation Molarity (M) = moles/volume (L), you can rearrange the equation to solve for volume (L) by dividing moles by the molarity. Then, convert the volume from liters to milliliters by multiplying by 1000. **

To prepare 400 ml of a 15% NaOH solution from a 20% NaOH stock solution, we can use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration, and V2 is the final volume of the solution. Plugging in the values, we get (20%)(V1) = (15%)(400 ml). Solving for V1, we find that V1 = (15%)(400 ml) / 20% = 300 ml. Therefore, 300 ml of the 20% NaOH stock solution is needed to prepare 400 ml of a 15% NaOH solution. **

In this case, NaOH is correct. NaOH is a strong base, while acetate is a weak base. When titrating a strong acid with a strong base, NaOH is the appropriate choice as it will completely neutralize the acid. Acetate would not be as effective in this scenario due to its weaker basic properties. **